3x^2+8x-76=180

Solution for 3x^2+8x-76=180 equation:

3x^2+8x-76=180

We move all terms to the left:

3x^2+8x-76-(180)=0

We add all the numbers together, and all the variables

3x^2+8x-256=0

a = 3; b = 8; c = -256;
Δ = b2-4ac
Δ = 82-4·3·(-256)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-56}{2*3}=\frac{-64}{6}
=-10+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+56}{2*3}=\frac{48}{6}
=8
$